Question

can solve this .....

Answer 1

1. The sum of all angles in a triangle = 180°
    Therefore 105° + 30° + 3rd angle = 180°
     3rd angle = 180° - 135° =   45°
2. Let the other two equal angles = x°
    Sum of all angles in a triangle = 180°
    130° + x° + x° = 180°
     2 x° = 50°
     ⇒ x = 25°
3. Ratio of three angles = 1:2:3
    Let the three angles are = 1 x°, 2 x°, 3 x°
    sum of all angles in a triangle = 180°
    1 x + 2 x + 3 x = 180
      6 x = 180 ⇒ x = 30°
     The three angles are 30°,60°,90°
4. 1. Exterior angle 110° = sum of 2 opposite interior angles 50 + x°
          x =110 - 50 = 60°
     2. x = 50°(vertically opposite angles are equal)
         50 + y + 70 = 180
        ⇒ y = 60°
     3. 90 + x + x = 180
          ⇒ 2 x = 90 ⇒ x = 45°
     4. exterior angle y = 45+35 = 80°
         x + 80° = 180° (since straight line)
         ⇒ x = 100°
     5. x+x+x = 180°
         3 x = 180° ⇒ x = 60°
     6. y = 45°(vertically opposite angles are equal)
         x + 45° = 180°
         x = 135°