Question

can some One help me by solving it step by step please? ?​

Answer 1

Step-by-step explanation:

$\frac{2x}{x - 3} = \frac{2x + 3}{x - 2} \\ = > 2x(x - 2) = (x - 3)(2x + 3) \\ = > \: {2x}^{2} - 4x \: = \: {2x}^{2} + 3x - 6x - 9 \\ = > {2x}^{2} - 4x = {2x}^{2} - 3x - 9 \\ = > {2x}^{2} - {2x}^{2} = 4x - 3x - 9 \\ = > x - 9 = 0 \\ = > x = 9$

Answer 2

$\huge\tt\red{A}\tt\pink{N}\tt\blue{S}\tt\green{W}\tt\purple{E}\tt\orange{R}$

$\begin{gathered} \frac{2x}{x - 3} = \frac{2x + 3}{x - 2} \\ 2x(x - 2) (x - 3)(2x + 3) \\ \: {2x}^{2} - 4x \: \: \\ {2x}^{2} + 3x - 6x - 9 \\ {2x}^{2} - 4x = {2x}^{2} - 3x - 9 \\ {2x}^{2} - {2x}^{2} 4x - 3x - 9 \\ x - 9 = 0 \\ x = 9\end{gathered}$