can some one solve this plzzzz
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Hey there! Here is your answer.
/_OAB = 28°
/_OAB = 90°
In ∆AOB,
=> /_OAB + /_AOB + /_OBA = 180°
=> 28° + 90° + /_OBA = 180°
=> /_OBA = 180° - 118°
=> /_OBA = 62 °
/_B = 90°
•°• /_ OBC = 90° - 62° = 28 °
Hope this answer will help you!
Plz mark as brainliest
#Be Brainly✌️
@Astudent
/_OAB = 28°
/_OAB = 90°
In ∆AOB,
=> /_OAB + /_AOB + /_OBA = 180°
=> 28° + 90° + /_OBA = 180°
=> /_OBA = 180° - 118°
=> /_OBA = 62 °
/_B = 90°
•°• /_ OBC = 90° - 62° = 28 °
Hope this answer will help you!
Plz mark as brainliest
#Be Brainly✌️
@Astudent
azizabuthagirpeqsce:
thanks alot
It's my pleasure
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