Can some one tell what is the answer for 2x-1/3=1/5=x
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4/5
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Now, find the value of x by considering the given equation,= 2x – (1/3) = (1/5) – x chromosome
Transposing – (1/3) to RHS and it becomes (1/3) and – x to LHS it becomes x
= 2x + x = (1/5) + (1/3)
= 3x = (3 + 5) / 15
= 3x = 8/15
Multiplying both side by (1/3)
= 3x × (1/3) = (8/15) × (1/3)
= x = (8/45)
By substituting (8/45) in the place of x in given equation, we get
LHS,
= 2 × (8/45) – (1/3)
= (16/45) – (1/3)
= (16 – 15) / 45
= (1/45)
RHS
= (1/5) – (8/45)
= (9-8) / 45
= (1/45)
By comparing LHS and RHS
= (1/45) = (1/45)
∴ LHS = RHS
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