can somebody explain why acceleration is taken 2a in the second equation for mass m
question 19
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As you divide Tension.
Acceleration is also divided in 2 parts.
Take acceleration of mass M as a, then acceleration of mass, m will be doubled, as Tension is halved.
Suppose acceleration of mass, m be "y":
Then it is calculated as below:
2T × a = T × y
y = 2a
So, acceleration of mass, m will be 2 time acceleration of mass, M.
(if you still have any doubt, feel free to comment)
Thankyou!!!
Acceleration is also divided in 2 parts.
Take acceleration of mass M as a, then acceleration of mass, m will be doubled, as Tension is halved.
Suppose acceleration of mass, m be "y":
Then it is calculated as below:
2T × a = T × y
y = 2a
So, acceleration of mass, m will be 2 time acceleration of mass, M.
(if you still have any doubt, feel free to comment)
Thankyou!!!
Raja395:
Ya, it's true
F = ma
Don't confuse like that.
ok got it
See, Here F = ma is the actual force. But I'm telling that as we considered T on mass,m and then we found, 2T on mass, M.
Similarly, we considered, acceleration,a of mass, M, and then we get acceleration 2a of mass, m.
If you still have any doubt, please ask
Don't ignore your doubts
Else, Good night...!!! :)
no no its all clear thanks :) means a lot
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