Question

can somebody please help me​

Answer 1

Answer →

Given that -

• AB|| DE
• Angle ACB = 53°
• Angle CDE = 45°
• Angle B = X
• Angle E = 3y +1

Now AB||DE then

Angle ABC = Angle CDE ( alternate angle)

So value of X is 45°

Now in ∆ ABC

Angle A + B +C = 180°

[ Interior angle sum property]

A + 45° + 53° = 180°

Now angle A is the alternate angle of angle E

So angle A = angle E

A = 3y+1

→ 3y+1 + 98° = 180°

→ 3y = 180-99°

→ 3y = 81°

→ y. = 27°

$\huge\mathbb{Hope\:it\:helps}$

Answer 2

Answer:

Step-by-step explanation:

ACB=DCE.....(opposite angles)

Therefore, 53°=DCE

Now, ABC=CDE....( alternate angles)

Therefore, x°=45°

Sum of all triangles =180°

Thus, 53+45+A=180

98+A=180

A=180-98

=72°

Thus BAC=DEC...(alternate angles)

72°=DEC