Math, asked by longkumertoshi05, 1 day ago

Can Somebody please help me
I need a brief explanation

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Answers

Answered by ImperialGladiator
24

Question:

A 60 litres of alcohol and water contains 20 litres of alcohol. How much alcohol must be added to produce a solution of 50% alcohol?

Answer:

20 litres.

Explanation:

Given,

  • Total solution = 60 litres
  • Amount of alcohol = 20 litres.

Let's assume the required amount of alcohol must be added is x litres.

New amount of alcohol = (x + 20) litres.

New solution = (x + 60) litres.

According to the question,

New amount of alcohol is 50% of the total new solution.

 \rm \therefore \: 50\% \: of \:  (x + 60) = (x + 20)

Solving for x :-

 \rm \implies \:  \dfrac{1}{2} (x + 60) = (x + 20)

 \rm \implies \: (x + 60) = 2(x + 20)

 \rm \implies \: x + 60 = 2x + 40

 \rm \implies \: 60  - 40= 2x - x

 \rm \implies \: 20= x

Required answer: 20 litres

____________________________

Answered by Anonymous
10

Answer:

Question :

A 60 litres of alcohol and water contains 20 litres of alcohol. How much alcohol must be added to produce a solution of 50% alcohol?

Given :

  • Total solution = 60 litres
  • Alcohol in solution = 20 litres

To Find :

  • Amount of alcohol must be added to produce a solution of 50% alcohol.

Solution :

Let x litre alcohol must be added to produce 50% alcohol. So, the new amount of solution and alcohol will be :

  • ➝ Alcohol = (x + 20) litres
  • ➝ Solution = (60 + x) litres

Now, According to the question :

 \begin{gathered}\qquad\implies{x + 20 = 50\%(60 + x)} \\  \\ \qquad\implies{x + 20 =  \dfrac{50}{100}(60 + x)} \\  \\ \qquad\implies{x + 20 =  \cancel{\dfrac{50}{100}}(60 + x)} \\  \\ \qquad\implies{x + 20 = \dfrac{1}{2}(60 + x)} \\  \\ \qquad\implies{2(x + 20) =(60 + x)} \\  \\ \qquad\implies{(2x  + 40)=(60 + x)} \\  \\ \qquad\implies{2x - x = 60 - 40} \\  \\ \qquad\implies{x = 20}\end{gathered}

Hence, 20 litres of alcohol must be added to produce a solution of 50% alcohol.

\underline{\rule{220pt}{4pt}}

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