Math, asked by honokahikarichan, 6 months ago

Can somebody please help T_T

Homogeneous Differential Equation

y(x^2+y^2)dx+x(3x^2-5y^2)dy=0, when x=2 , y=1

The answer is: 2y^5-2x^2y^3+3x​

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Answered by Anonymous
2

see this pic its also helps you dude.

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Answered by Anonymous
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Differential Equations

Solving Homogeneous Differential Equation

Solve: (x^3 + 3xy^2) dx + (...

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Solve: (x3+3xy2)dx+(y3+3x2y)dy=0

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ANSWER

⇒dxdy=−(y3+3x2y)(x3+3xy2)=−3x2y(3x2yy3+1)3xy2(3xy2x3+1)=−x(3x2y2+1)y(3y

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