Question

can someone answer me.....will be mark as brainliest

Answer 1

let √6+√(6.... = y
now if you take the first 6 and see the rest of the series then it is again y i.e.., the question again so we have the equation
      √(6+y) = y
squaring on both sides we have y²= 6+y
                                                y²-y-6=0 
                                                y²-3y+2y-6=0
                                                y(y-3)+2(y-3)=0
                                               (y-3)(y+2)=0
                                           ⇒y=3 or y=-2
    

Answer 2

PROOF
___________________________
To solve this type of problems,

First ,find two consective factor of that no.

In this case, The consecutive factor is 2×3

Then, the greater no. between them is the answer.
In this case ,The answer is 3.

Hope this will help.