can someone answer this

Answers
Slope = fo/xo
Eq = F - fo = fo/xo. ( x - 2xo)
F = m v dv/dx
F = fo/xo. ( x - 2xo) + fo)
Fdx = m v dv
integrate
fo/xo ( x^2/2 - 2xo x) + fo x = m v^2/2 + c
V at xo = √2 fo xo/m
fo/xo ( xo^2/2. - 2 xo^2) + fo xo = fo^2 xo^2/m + c
fo /xo ( -3/2. xo^2) + fo xo - fo^2 xo^2/m = c
- 3/2 fo xo + fo xo - fo^2 xo^2 /m = c
- fo xo/2 - fo ^2 xo^2/m = c
-fo xo ( 1/2 + fo xo/m) = c
Now put x= 4 xo
fo/xo ( 16 xo^2/2 - 8 xo^2) + 4 fo xo = mv^2/2 - foxo ( 1/2 + fo xo/m)
4 fo xo+ foxo ( 1/2 + foxo/m) = mv^2/2
4 foxo + foxo /2 + fo^2 xo^2 /m = mv^2/2
9/2. foxo + fo^2 xo^2/m = m v^2/2
9 foxo + 2 fo^2 xo^2/m= mv^2
9 fo xo/m + 2 fo^2 xo^2 /m^2 = v^2
(√2 fo xo /m. + 9/2√2)^2 - 81/8 = v^2
2√2 fo xo/m + 81/8 - 81/8 = v^2( assuming 1/√2 to be small) ,exonents multiplied when small
V= 2√( √2 foxo/m)
So (A)