Can someone answer this as quickly as possible? (Co-ordinate Geometry question)
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Answer:
8x-3y-10 =0
Step-by-step explanation:
The equations of sides of a rectangle are
x
1
=−1,x
2
=2,y
1
=2,y
2
=6.
These lines form a rectangle when they intersect at A, B, C, D respectively
Now,
The co-ordinates of A, B, C and D will be (−1,−2),(2,−2),(2,6),(−1,6) respectively.
And, AC and BD are its diagonals.
Slope of the diagonal AC
=
x
2
−x
1
y
2
−y
1
=
(2+1)
(6+2)
=
3
8
=m
So, the equation of AC will be
y−y
1
=m(x−x
1
)
y+2=
3
8
(x+1)
3y+6=8x+8
⇒8x−3y+2=0
Slope of the diagonal BD
=
x
2
−x
1
y
2
−y
1
=
(−1−2)
(6+2)
=
3
−8
=m
So, the equation of BD will be
y−y
1
=m(x−x
1
)
y−6=
3
−8
(x+1)
3y−18=−8x−8
⇒8x−3y−10=0
.
sorry but i can't prepare graph
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