Question

can someone answer this pls​

Answer 1

Answer:

x=5 y =2

Step-by-step explanation:

Taking LHS

root3+root 2/root3-root2

(root3+root2)×(root3+root2)÷(root3-root2)(root3+root2)

3+2+2×root3×root2÷3-2

{above situation has arisen because of the identity (a+b)^2=a2+b2+2ab and a^2-b^2=(a-b)(a+b)}

5+2root6---(LHS)

now equating both LHS and RHS we get

5+2root6=x+yroot6

so the value of x=5 and y=2