Question

can someone answer this question

Answer 1

Step-by-step explanation:

solution:-

$\frac{7 + 3 \sqrt{5} }{3 + \sqrt{5} } - \frac{7 - 3 \sqrt{5} }{3 - \sqrt{5} } \\ \frac{(3 - \sqrt{5} )(7 + 3 \sqrt{5}) - (7 - 3 \sqrt{5})(3 + \sqrt{5} ) }{(3 + \sqrt{5} )(3 - \sqrt{5}) } \\ \frac{(21 + 9 \sqrt{5} - 7 \sqrt{5} - 3 \sqrt{5} \times \sqrt{5} ) - (21 + 7 \sqrt{5} - 9 \sqrt{5} - 3 \sqrt{5} \times \sqrt{5} }{(3) {}^{2} - ( \sqrt{5)} {}^{2} } \\ \frac{(21 + 2 \sqrt{5} - 15) - (21 - 2 \sqrt{5} - 15)}{9 - 5} \\ \frac{(6 + 2 \sqrt{5} ) - (6 - 2 \sqrt{5}) }{4} \\ \frac{ \not{6} + 2 \sqrt{5} - \not6 + 2 \sqrt{5} }{4} \\ \frac{0 + 4 \sqrt{5} }{4 } \\ 0 + \frac{4 \sqrt{5} }{4} \\ 0 + \sqrt{5} \\ a = 0 \: \: and \: \: b = 1$

i hope u will find ur answer