Question

Can someone answer this question.
Don't spam.
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Answer 1

Step-by-step explanation:

in Δ APB and Δ AQB

angle B= angle Q=90°

angle PAB = angle QAB (angle A bisect by AB)

AB =AB (common)

Δ APB =~ Δ AQB (by AAS)

BP = BQ by C. P. C. T