Math, asked by theolympians, 10 months ago

Can someone answer this question please

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Answered by aviswan60
2

Answer:

volume of water in cylindrical tub=volume of the hemisphere+volume of the cone

={[(2×22×7×7×7)/(3×7×2×2×2)]+[(1×22×7×7×5)/(3×7×2×2)]}

=(539/6 +385/6)

=924/6

=154 cm³

volume of tub =(22×5×5×9.8)/7

=770 cm³

volume of water left in the tub=volume of tub -volume of solid immersed

=770-154

=616 cm³

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