Question

can someone answer this question?pllss​

Answer 1

Answer:

the first term

= (x^a / x^b)^(a+b)

=( x^(a - b))^(a + b)

= x^((a - b)(a + b))

= x^(a^2 - b^2)

similarly second term

= x^(b^2 -c^2)

third term

= x^(c^2 - a^2)

the three terms are in multiplication with same base, so their exponents will be added

x^ (a^2 - b^2 + b^2 - c^2 + c^2 - a^2)

= x^0

= 1

Answer 2

$\star\:\:\:\bf\large\underline\blue{Question:-}$

• Evaluate the following.

$\star\:\:\:\bf\large\underline\blue{Solution:-}$

${( \frac{ {x}^{a} }{ {x}^{b} } )}^{a + b} \times {( \frac{ {x}^{b} }{ {x}^{c} } )}^{b + c} \times {( \frac{ {x}^{c} }{ {x}^{a} } )}^{a + c}$

$= {({x}^{a - b})}^{a + b} \times {( {x}^{b - c})}^{b + c} \times {({x}^{c - a})}^{c + a}$

$= {x}^{ {a}^{2} - {b}^{2} } \times {x}^{ {b}^{2} - {c}^{2} } \times {x}^{ {c}^{2} - {a}^{2} }$

$= {x}^{ {a}^{2} - {b}^{2} + {b}^{2} - {c}^{2} + {c}^{2} - {a}^{2} }$

$= {x}^{0}$

$= 1$

$\star\:\:\:\bf\large\underline\blue{Answer:-}$

• Answer for the problem is 1.