Question

can someone answer this questions please??

Answer 1

Resistance $(R_1)$ = 3 Ω

Resistance $(R_2)$ = 6 Ω

In parallel, the equivalent resistance:

$\frac{1}{R_e_q} =\frac{1}{R_1} + \frac{1}{R_2}$

$\frac{1}{R_e_q} =\frac{1}{3} + \frac{1}{6}$

$\frac{1}{R_e_q} = \frac{3}{6}$

a) $R_e_q = 3$ Ω

b) The potential difference across 3 Ω resistor is 12 V.

$Current(I) = \frac{V}{R}$

$Current(I) = \frac{12}{3}$

I = 4 A

Hence, the current through 3 Ω resistor is 4 A