Question

can someone do (i) &(ii)​

Answer 1

Answer:

Step-by-step explanation:

We have BC||AD ...........(1)      [Sides of a parallellogram]

EF||BC .............(2)        [Given]

From(1) and(2),we have

AD||EF

(i) In ΔABD,AD||EF

  ∴AE/EB=EF/AD   [Thales theorem]

  ⇒1/2=EF/AD

  ⇒EF:AD=1:2

(ii) ar(ΔBEF):ar(ABD)=(BE:AB)²

                                =(2:3)²

                                =4:9