Can someone do this question without using area of triangle formula
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Yes I can do this without using area of triangle formula
I will use the concept of slopes to find k .
We know that
- If three points are collinear then slopes of point is always equal.
Here We have
- A = (k + 1 , 2k)
- B = (3k , 2k + 3)
- C = (5k - 1 , 5k)
Slope of the line joining two points (x₁ , y₁) and (x₂, y₂)
= (y₂ - y₁) / (x₂ - x₁)
Slope of AB = [2k - (2k + 3)] / [3k - (k + 1)]
= [2k - 2k - 3] / [3k - k - 1]
= -3 / 2k - 1
Slope of BC = [5k - (2k + 3)] / [(5k - 1) - 3k]
= [5k - 2k - 3] / [5k - 1 - 3k]
= [3k - 3] / [2k - 1]
Slope of AB = Slope of BC
-3 / 2k - 1 = (3k - 3) / (2k - 1)
-3 = 3k - 3
0 = 3k
k = 0
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