can someone explain me how to do this sum
three resistors of 3 ohm each areconnected to a battery of 3v .calculate the current drawn from the battery
riddhiya:
kalpesh
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Answered by
2
Yeah sure.
Case 1 : Series connection of resistors
Total resistance = 3 +3 +3 = 9 ohms
Potential difference = 3V
Current = v/r = 3/9 = 1/3 = 0.33A
Case 2 : Parallel connection of resistors
Total resistance = 1/R = 1/3 + 1/3 + 1/3
= 3/3 = 1 ohm
Potential difference = 3V
Total current = v/r = 3/1 = 3A
Current through each resistor = v/r = 3/3 = 1A
Since all have equal resistance the same current only flows in all the resistors.
Hope it helps!!
Cheers!!
Case 1 : Series connection of resistors
Total resistance = 3 +3 +3 = 9 ohms
Potential difference = 3V
Current = v/r = 3/9 = 1/3 = 0.33A
Case 2 : Parallel connection of resistors
Total resistance = 1/R = 1/3 + 1/3 + 1/3
= 3/3 = 1 ohm
Potential difference = 3V
Total current = v/r = 3/1 = 3A
Current through each resistor = v/r = 3/3 = 1A
Since all have equal resistance the same current only flows in all the resistors.
Hope it helps!!
Cheers!!
Answered by
29
Answer:
yes it is true........
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