can someone give me the structure of BaXeO6 ......
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Oxidation state of Ba in general =+2 and of O=−2
Applying formula, Sum of total oxidation state of all atoms = Overall charge on the compound.
Let oxidation state of Xe in BaXeO6 be x.
2+x+6(−2)=0,x=10
But oxidation state 10 is not possible for Xe . In this case the oxidation state of Xe is equal to maximum possible oxidation state for Xe=+8
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