Can someone give step by step answer for this
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*A2A*
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[math](ax^3 + bx^2 + cx + d)^2 \tag{1}[/math]
Comparing coefficients for [math]x^6, x^5, x^4, x^3, x^2[/math], it is easy to see that,
[math]\displaystyle a = 4, b = 0, c = 1, d = -\frac{1}{4} \tag{2}[/math]
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[math]\displaystyle \left(4x^3 + x - \frac{1}{4}\right)^2 \tag{3}[/math]
Subtract the given expression from (3) to get the required answer.
PLS MARK BRAINLIEST
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