Question

can someone help me as my math icse 9 std paper is tomorrow ​

Answer 1

Answer:

tan12°tan38°tan52°tan60°tan78°

using complementary angles formula of trigonometry

so

tan(90-78).tan(90-52).tan52°.tan60° tan78°

= cot78°.cot52°.tan52°.tan60°.tan78°

after cancelling

= tan60°

= √3

hope this will help you

pleeeease mark it as brainliest

Answer 2

Answer:

as we know

• tan 12°.tan78°.tan52°.tan38°.tan60°
• tan 12.tan(90°-12°).tan52°.tan(90°-52°).tan60°(tan(90-θ) = cotθ)
• tan12.cot12.tan52.cot52.tan60
• 1*1.√3 (tan θ.cotθ=1 & tan60=√3)
• √3