Question

Can someone help me how to do the 3 one

Answer 1

I hope it helps you..

plzz follow me

Answer 2

Question : The sum of the digits of a two - digit number is 9. Also, nine times this number is twice the number obtained by reversing the order of the digits. Find the number.

Solution :

Given,

The sum of the digits of a two digit number is 9.

let the two numbers be x and y

Then the number is 10x + y

The sum of the digits = 9

According to the problem,

x + y = 9 -------(1)

When the number is reversed = 10y + x

Then nine times this number is twice the number obtained by reversing the order of the digits.

9(10x + y ) = 2(10y + x )

90x + 9y = 20y + 2x

90x - 2x = 20y - 9y

88x = 11y

8x = y ----(2)

Subtitute y in eq - (1)

x + (8x) = 9

9x = 9

x = 1

substitute x in eq ---(2)

8(1) = y

y = 8

Therefore, the number = 10(1) + (8) = 18