Math, asked by Anonymous, 9 months ago

can someone help me in this question please​

Attachments:

Answers

Answered by An2528
1

Answer:

6/3root2-2root3=3root2-a*root3 [Given]

6=(3root2-a*root3)(3root2-2root3)

6=18-3a*root6-6root6+6a

12=3a*root6+6root6-6a

12=3a*2.44+6*2.44-6a

12=7.32a+14.64-6a

-1.32a=2.64

a=-2

Hope it will help you

Mark the brainliest

Answered by Anonymous
1

Answer:

 \frac{6}{3 \sqrt{2}  - 2 \sqrt{3} }  = 3 \sqrt{2}  - a \sqrt{3}  \\  \\  \\  6 = (3 \sqrt{2}  - a \sqrt{3} )(3 \sqrt{2}  - 2 \sqrt{3} ) \\  \\  \\  \\ 6 = 18 - 6 \sqrt{6}  - 3a \sqrt{6}  - 3a \\  \\ 3a \sqrt{6}  - 3a = 18 - 6 \sqrt{6 }  - 6 \\  \\ 3a( \sqrt{6}  - 1) = 6(3 -  \sqrt{6}  - 1) \\  \\ 3a( \sqrt{6}  - 1) = 6(2 -  \sqrt{6} ) \\  \\  \\ a =  \frac{6(2 -  \sqrt{6}) }{3( \sqrt{6 - 1)} }  \\  \\ a =  \frac{2(2 -  \sqrt{6} )}{ \sqrt{6}  - 1}

please mark me brainlist ✔️✔️

Similar questions