Math, asked by Anonymous, 4 months ago

Can someone help me in this question?

= \sf{\dfrac{\sqrt{\sqrt5 - 2} + \sqrt{\sqrt5 + 2}}{\sqrt{\sqrt5 + 1}}}

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Answers

Answered by llNidhill
13

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 \huge \bold  \color{lime}{Solution:-}

 \red{= \sf{\dfrac{\sqrt{\sqrt5 - 2} + \sqrt{\sqrt5 + 2}}{\sqrt{\sqrt5 + 1}}}} \\    {x}^{2}  =  \frac{ \sqrt{5} + 2 \sqrt{5}  - 2 + 2 \sqrt{( \sqrt{5}  + 2) \sqrt{5  } - 2 }   }{ \sqrt{5} + 1 }  \\  =   \frac{2 \sqrt{5}  + 2 \sqrt{5 - 4} }{ \sqrt{5}  + 1}  \\  =  \frac{2 \sqrt{5}  + 2 \sqrt{1} }{ \sqrt{5} + 1 }  \\  =  \frac{2(  \sqrt{5}  + 1 }{( \sqrt{5} + 1 }   = 2 \\   \bold\green \implies  \green{\: x =  \sqrt{2} }

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Answered by Anonymous
1

Please solve this one also!!

It's a humble request.

Thank you!!

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