Question

Can someone help me out with this problem - Find 2 numbers such that their mean proportion is 24 and third proportion is 1536

Answer 1

Let the two numbers be x and y.

Given that Mean proportion of two numbers is 24.

$= > \sqrt{xy} = 24$

= > x * y = 24

= > xy = 576

= > x = (576/y) ----- (1)

Given that Third proportion is 1536.

= > y^2 = x * 1536 ------ (2)

Substitute (1) in (2), we get

= > y^2 = (576/y) * 1536

= > y^3 = 576 * 1536

= > y^3 = 884736

= > y = 96.

Substitute y = 96 in (1), we get

= > x = (576/y)

= > x = (576/96)

= > x = 6.

Therefore, the two numbers are 6 and 96.

Hope this helps!