can someone help me solve this question..!! please
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For pure water
[H₃O⁺] = [OH⁻]
Kw = [H₃O⁺][OH⁻]
= 10^-8 × 10^-8
= 10^-16
Value of Kw = 10^-16
[H₃O⁺] = [OH⁻]
Kw = [H₃O⁺][OH⁻]
= 10^-8 × 10^-8
= 10^-16
Value of Kw = 10^-16
hareethha4591:
hey junaid , can you help me solve the other questions of this chapter..???
Ask your questions. If I can I will sure answer.
10^4M Hcl solution at 298 K is diluted 1000 times. the pH of the solution will be
(a) lie between 8 and 9 (b) lie between 6and 7 ( c ) remain unchanged (d) equal to 7
(b)
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