Can someone help me with the 10th question
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Just take a look on these solutions. It can be helpful for u
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7sin^2 + 3cos^2 = 4
= 7sin^2 + 3(1 - sin^2) = 4
= 7sin^2 + 3 - 3sin^2 = 4
= 4sin^2 = 1
= sin^2 = 1/4
= sin= 1/2 = P / H
Using Pythagoras find B
B^2 = H ^ 2 - P^2
B^2 = (2)^2 - (1)^2 = 3
B = root 3
Tan b = P / B
Tan b = 1 / root 3
Thanks
= 7sin^2 + 3(1 - sin^2) = 4
= 7sin^2 + 3 - 3sin^2 = 4
= 4sin^2 = 1
= sin^2 = 1/4
= sin= 1/2 = P / H
Using Pythagoras find B
B^2 = H ^ 2 - P^2
B^2 = (2)^2 - (1)^2 = 3
B = root 3
Tan b = P / B
Tan b = 1 / root 3
Thanks
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