Question

Can someone help me with the following? It's really urgent so please put solutions so I can study it later
(7j^3 – 2) + (5j^3 – j - 3)
(8a^5 – 4) + (3a^5 + a – 2)
j^2(k^5 j^3)
(x -6)(x+9), X = 2
(8x^2 – 3x) – (5x -5 - 8x^2)
5x^3 (2x + 4y), X = 5, Y = 3
(3m^5 + 1) + (9m^5 + 3m -2)

Answer 1

Answer:

(7j^3 – 2) + (5j^3 – j - 3)

(8a^5 – 4) + (3a^5 + a – 2)

j^2(k^5 j^3)

(x -6)(x+9), X = 2

(8x^2 – 3x) – (5x -5 - 8x^2)

5x^3 (2x + 4y), X = 5, Y = 3

(3m^5 + 1) + (9m^5 + 3m -2)

Answer 2

$1. \: \rm{\small(7j^3 – 2) + (5j^3 – j - 3)}$

$\rm{ \small{7j^3 – 2+ 5j^3 – j - 3}}$

$\rm \small12j^3 – 5– j$

$2. \sf \small(8a^5 – 4) + (3a^5 + a – 2)$

$\sf \small8a^5 – 4 + 3a^5 + a – 2$

$\sf \small11 {a}^{5} - 6 + a$

$\frak{3. \: j^2(k^5 j^3)}$

$\frak{ {k}^{5} {j}^{6} }$

$4. \: \tt \small (x -6)(x+9), X = 2$

$\tt \small(2 -6)(2+9)$

$\tt \small- 4 \times 11$

$\tt \small - 44$

$5. \tt \small(8x^2 – 3x) – (5x -5 - 8x^2)$

$\tt \small(8(2)^2 – 3(2)) – (5(2) -5 - 8(2)^2)$

$\tt \small(8 \times 4 - 3 \times 2) - (10 - 5 - 8 \times 4)$

$\tt \small(32 - 6)(5 - 32 )$

$\small \tt26 \times ( - 27)$

$\tt \small - 702$

$6. \tt \small5x^3 (2x + 4y), X = 5, Y = 3$

$\tt \small5(5)^3 (2(5) + 4(3))$

$\tt \small5 \times 125(10 + 12)$

$\tt \small625 \times 22$

$\tt \small13750$

$\tt \small7. (3m^5 + 1) + (9m^5 + 3m -2)$

$\tt \small 3m^5 + 1 + 9m^5 + 3m -2$

$\tt \small12 {m}^{5} - 1 + 3m$