Question

can someone help me with this

Answer 1

Answer:

by hypothesis therom

$x {}^{2} + 12 {}^{2} = 16 {}^{2}$

$x {}^{2} = 16 {}^{2} - 12 {}^{2}$

$x {}^{2} = 256 - 144$

$x {}^{2} = 112$

$x = \sqrt{112}$

Answer 2

Given:-

• Triangle is Right Angled.
• Hypothenuse = 16.
• Sides are 12 & x.

To Find:-

• Value of x.

Solution:-

WKT

$\boxed{\sf{\star\;(Hypothenuse)² = (Side)²+(Side)²}}$

$→\;{\sf{(16)² = (12)²+x²}}$

$→\;{\sf{256 - 144 = x²}}$

$→\;{\sf{\sqrt{112} = x}}$

$→\;{\sf{x = 4\sqrt{7}}}$

• Value of x is $\red{\bf{4\sqrt{7}\;units}}$

$\Large{✓}$

Hope It Helps You ✌️