CAN SOMEONE HELP ME WITH THIS PLEASE IT DUE IN 15 MINS
solving systems of three equations with elimination
-x-5y+4z=19
4x-5y+4z=19
x+5y=-z=-20
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Answer:
x-5y+4z=19___(1)
4x-5y+4z=19__(2)
x+5y=-z=-20__(3)
from 1&3
x-5y+4(-x-5y)=19
x-5y-4x-20y=19
-3x-25y=19____(4)
multiply (3) by 5
so, 5x+25y=-100___(5)
now add (4)&(5)
2x=81; x=81/2 put into (3)
x+5y=-20
(81/2)+5y=-20
5y=-20-(81/2)
5y=(-40-81)/2
5y= -121/2
y= -121/10
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