Math, asked by velamahema, 1 month ago

Can someone please answer this its urgent
please​

Attachments:

Answers

Answered by Anonymous
1

Answer:

For finding that which figure encloses more area we will have to find the area of both the figures -

Area of square = side * side

= 4 cm * 4 cm

= 16 cm square

Area of rectangle = length * breadth

= 3 cm * 4 cm

= 12 cm square

As the area of square is more than the area of the rectangle, the square will enclose more area.

If it helps you, please mark as brainliest.

Answered by Anonymous
33

\large\sf\underline{Question\::}

Which figure encloses more area : A square of side 4 cm or A rectangle of length 3 cm and breadth 4 cm.

Options :

  • Rectangle

  • Square \bf\:☑

  • Both of them

  • Neither a nor b

\large\sf\underline{Answer\::}

  • A \large{\mathfrak\blue{Square}} encloses larger area.

___________________________‎

\bf\:Step\:wise\:explanation\::

\large\sf\underline{Given\::}

  • Side of a square = 4 cm

  • Length and breadth of a rectangle = 3 cm and 4 cm respectively

\large\sf\underline{To\:find\::}

  • Whose area is larger between square and rectangle

\large\sf\underline{Concept\::}

Here we are given the measure of side of a square and length and breadth of a rectangle. We are asked to find which of these two geometric figure encloses larger area. In order to do so we would find the area of square and rectangle separately. Doing so we can easily compare both the values and decide which one is larger. Let's begin !

\large\sf\underline{Formula\:to\:be\:used\::}

  • Area of a square = \small{\mathfrak\purple{(side)^{2}}}

  • Area of a rectangle = \small{\mathfrak\purple{length \times breadth}}

\large\sf\underline{Solution\::}

Let's first calculate the area of square :

\sf\implies\:Area\:of\:square\:=\:(side)^{2}

  • Substituting the values we are given

\sf\implies\:Area\:of\:square\:=\:(4)^{2}

\small{\underline{\boxed{\mathrm\red{\implies\:Area\:of\:square\:=\:16\:sq.cm}}}}

Now let's calculate the area of rectangle :

\sf\implies\:Area\:of\:rectangle\:=\:length \times breadth

  • Substituting the values we are given

\sf\implies\:Area\:of\:rectangle\:=\:3 \times 4

\small{\underline{\boxed{\mathrm\red{\implies\:Area\:of\:rectangle\:=\:12\:sq.cm}}}}

So comparing the area of square and rectangle i.e., 16 sq. cm and 12 sq. cm, Clearly the square encloses larger area.

___________________________‎

!! Hope it helps !!

Similar questions