Question

can someone please answer this question?

thank you :)

Answer 1

R= 3ohm

as current in series is same,,
current across 6ohm resistor is 12V/6 ohm = 2Amp.

it must be same in R ohm,,, therefore R = 6V/ 2A = 3ohm

Ammeter reading is 2Amp.

Potential Difference is 18V

Answer 2

(a) ∵ I = V/R and remains the same for the resistors in SERIES

∴  6V / R = 12V / 6 ohm

∴ R = (6×6/12) ohm

       = 3 ohm

(b) Reading of ammeter = Current through it (I)

R(equi.) = (3 + 6) ohm

             = 9 ohm

V = (6+12) V

   = 18 V

∴ I = V/R

      = (18/9) A = 2A

(c) potential drop = 6V + 12V = 18V