can someone please answer this question with working
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Hope this will help you...
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I hope this will help you
Let the lenght of two parallel lines be x and x+5
Area of trapezium =(sum of parallel lines)/2 * hieght
270/12=(sum of parallel lines)/2
22.5*2=x+x+5
50=2x+5
45=2x
22.5=x
Lenght of parallel lines =20,25
Let the lenght of two parallel lines be x and x+5
Area of trapezium =(sum of parallel lines)/2 * hieght
270/12=(sum of parallel lines)/2
22.5*2=x+x+5
50=2x+5
45=2x
22.5=x
Lenght of parallel lines =20,25
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