can someone please answer this :- solve using elimination method 3x-2y=12,4x-5y=16
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(3x-2y=12)....Multiply this equation by 5
=15x-10y=60......eqn1
(4x-5y=16)....Multiply this equation by 2
=8x-10y=32.....eqn2
Using elimination method....
By subtracting eqn2 from eqn 1
15x-10y=60
-(8x)-(-10y)=-(32)
_______________. (10y got cancelled)
7x=28
=>x=4
Using eqn2 we can find y
4x-5y=16
16-5y=16
5y=16-16
5y=0
y=0
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