Question

can someone please explain me this ?​

Answer 1

a) diagram

Coulomb measured the force between two point charges and found that it varied inversly

as the square of the distance between the charges and was directly proportional to the product of the

magnitude of two charges and acted along the line of joining the two charges.

Thus if two point charges q1 and q2 are separated by a distance r in vacuum,

the magnitude of the force F between them is given by,

$F = k \frac{ |q_{1} \times q _{2} | }{ {r}^{2} } \: (eqn. \: 1)$

The constant k in eqn.(1) is usually put as

$k = \frac{1}{4\piε_{0}}$

,so that Coulombs law is written as

$F = \frac{1}{4\piε_{0}} \frac{ |q_{1} \times q_{2}| }{ {r}^{2} } (eqn.2)$

where εo is permitivity of free space and it is given by, εo =

$8.854× {10}^{ - 12} {C}^{2} {n}^{ - 1} {m}^{ - 2}$Since force is vector, we need to write Coulombs law in vector notation.

{The rest is in the attachment}

Hope it helps

Answer 2

Answer:

4 + 4x^6 + 10x^2. x^4 + 4x^4 +x^6.