Question

CAN someone please help​

Answer 1

Answer:

Let the numbers be x and y

so

equation 1= x+y= 10

equation 2=

$10x + y + 54 = 10y + x \\ 10x + y - 10 - x = ( - 54) \\ 9x - 9y = ( - 54) \\ x - y = \frac{ - 54}{9} \\ x - y = 6$

Equation 2= x-y= 6

so

$x + y = 10 \\ x - y = 6 \\ - \:\: \: + \: \: \: \: \: - \: \\ \\ so \: 2y = 4 \\ y = \frac{4}{2} \\ y = 2 \\ first \: no \: is \: 2 \: and \: other \: is \\ x + 2 = 10 \\ x = 10 - 2 \\ x = 8 \\ so \: the \: number \: is \: 28$

Solved from linear equations in two variable

Step-by-step explanation:

Let the first no be x

so second no= (10-x)

Now

$10(x) + (10 - x) + 54 = 10(10 - x) + x \\ 10x + 10 - x + 54 = 100 - 10x + x \\ 9x + 64 = 100 - 9x \\ 9x + 9x = 100 - 64 \\ 18x = 36 \\ x = \frac{36}{18} \\ x = 2 \\ so \: the \: first \: no \: is \: 2 \\ second \: no = (10 - x) = (10 - 2) = 8 \\ so \: the \: number \: is \: 28$

Solved From Linear equations in one variable.

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