Question

Can someone please help me?​

Answer 1

We know that Sum of angles of a quadrilateral is = 360°

In the quadrilateral ABCD

Given, ∠C =100° and ∠D = 50°

∠A + ∠B + ∠C + ∠D = 360°

∠A + ∠B + 100° + 50° = 360°

∠A + ∠B = 360° – 150°

∠A + ∠B = 210° ……. (Equation 1)

Now in Δ APB

½ ∠A + ½ ∠B + ∠APB = 180° (since, sum of triangle is 180°)

∠APB = 180° – ½ (∠A + ∠B)………. (Equation 2)

On substituting value of ∠A + ∠B = 210 from equation (1) in equation (2)

∠APB = 180° – ½ (210o) = 180° – 105° = 75°

∴ The measure of ∠APB is 75°.

Answer 2

Answer:

hope it is helpful to you ☺️