Question

Can someone please help me with all of these questions? I've been struggling with them for hours now. And also work must be shown for all of them.

Answer 1

Answer:

In the first image the area is

10 × 3 + 5 × 12 + 7 × 3 (the parts are formed as the lower rectangle, the upper rectangle, and the middle 13 side rectangle)

30 + 60 + 21

111 m^2

In the second image the angle is,

Using alternative interior angle 154° is the angle between the equal lines of triangle,

As lines are equal, angels opposite to them will also be equal so the other 2 angles are 13° each.

Now on the line CD,154° + 13° = 167° and it is equal to y using alternative interior angle.

Therefore, y = 167°

In the 3rd image,

Angle DHG = 50° alternative interior angle

Angle DGH = 80° Linear Pair

Now, using angle sum property we get GDH = 50°

Since, DHG & GDH are 50° or equal DG & GH are also equal.

In the 4th image,

Considering the trapezoid as a rectangle and triangle combination. And the x is divided in 2 parts 9 cm in the rectangle and the triangle has (x-9)cm.

In the 9 × 5 rectangle , area is 45cm^2.

Area remaining for triangle is 55-45 = 10cm^2

Area of triangle = 1/2 × base × height

10 = 1/2 × 5 × (x-9)

(x-9) = 10 × 2 / 5

x - 9 = 4

x = 13 cm

In the 5th image,

Plz comment on the answer whether the 4cm is height or the 3rd side. So, that I can solve it for u.