Can someone please help me with all of these questions? I've been struggling with them for hours now. And also work must be shown for all of them.
Answers
Answer:
In the first image the area is
10 × 3 + 5 × 12 + 7 × 3 (the parts are formed as the lower rectangle, the upper rectangle, and the middle 13 side rectangle)
30 + 60 + 21
111 m^2
In the second image the angle is,
Using alternative interior angle 154° is the angle between the equal lines of triangle,
As lines are equal, angels opposite to them will also be equal so the other 2 angles are 13° each.
Now on the line CD,154° + 13° = 167° and it is equal to y using alternative interior angle.
Therefore, y = 167°
In the 3rd image,
Angle DHG = 50° alternative interior angle
Angle DGH = 80° Linear Pair
Now, using angle sum property we get GDH = 50°
Since, DHG & GDH are 50° or equal DG & GH are also equal.
In the 4th image,
Considering the trapezoid as a rectangle and triangle combination. And the x is divided in 2 parts 9 cm in the rectangle and the triangle has (x-9)cm.
In the 9 × 5 rectangle , area is 45cm^2.
Area remaining for triangle is 55-45 = 10cm^2
Area of triangle = 1/2 × base × height
10 = 1/2 × 5 × (x-9)
(x-9) = 10 × 2 / 5
x - 9 = 4
x = 13 cm
In the 5th image,
Plz comment on the answer whether the 4cm is height or the 3rd side. So, that I can solve it for u.