can someone please help me with this question
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work done = pressure × change in Volume
here...
P= pressure= 4atm = 4×10^5 N/m^2
change in Volume = 75-125 =-50L
we know that...
1m^3 =1000L
=> 1L = 10^-3 m^3
so ..
work done by the gas =
4 × 10^5 × (-50) × 10^-3
= -20000J
= -20kJ
so... the work done by the gas in expansion is 20kJ
hope it helps you..
here...
P= pressure= 4atm = 4×10^5 N/m^2
change in Volume = 75-125 =-50L
we know that...
1m^3 =1000L
=> 1L = 10^-3 m^3
so ..
work done by the gas =
4 × 10^5 × (-50) × 10^-3
= -20000J
= -20kJ
so... the work done by the gas in expansion is 20kJ
hope it helps you..
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