Can someone please help me with this question?
Potassium has a bcc structure with nearest neighbour distance 4.52A°. Its atomic weight is 39. It's density (in kg m^(-3)) will be?
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7
Use the density formula-
=(Z×M)/a^3×Na
Here Z=2 (bcc) ,
M=39g ,
d=√3a/2 (from here take out the value of 'a'.)
Na is Avogadro No.=6.02×10^23
Get the answer.
=(Z×M)/a^3×Na
Here Z=2 (bcc) ,
M=39g ,
d=√3a/2 (from here take out the value of 'a'.)
Na is Avogadro No.=6.02×10^23
Get the answer.
ScarletD:
some people said that z=4 as it is bcc...
No,FCC=4 and BCC =2
okay thank you so much
' a ' here is the edge length so 4.52 right?
No,d=4.52,calculate 'a' from the given formula of 'd' and 'a'
Answered by
1
For bcc,d=3–√a2
Or a=2d3–√
⇒2×4.521.732
⇒5.219A∘=522pm
ρ=z×Ma3×NA×10−30
⇒2×39(522)3×6.023×1023×10−30
⇒0.91g/cm3
⇒910kgm−3
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