Can someone please help with this question
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Answer:
i⟩ Re = 8.33Ω, I = 4.8A
Explanation:
i⟩ Re = 1
1/10 + 1/50
= 1
6/50
= 1
3/25
= 25/3
= 8.33 Ω
V = IR
40 = 8.33 I
I = 40/8.33
= 4.8 A
ii⟩ Across R1
V = IR
V = 4.8 × 10
V = 48v
∆V = (V - e.m.f) = 8v
Across R2
Same process
Across R3 add take the R2's voltage.
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