can someone please solve all the questions and send with full solutions
Answers
Step-by-step explanation:
1. Given that ∠BOD=90, so the top of the table is
4/3
of a circle of radius 60cm. Perimeter of the table =(
4/3 ×2πr+2r)cm=( 4/3
×2×3.14×60+2×60)cm
=(90×3.14+120)cm=402.6cm.
2. Given
Radius of enclosed four circles =7 cm
Diameter of a circle =14 cm
Length of rectangle =4(14)=56 cm [As four circles cover the length of rectangle ]
Width of rectangle =14 cm [As only one circle covers width of rectangle]
(a) Area of rectangle = Length × Width
=56×14=784 cm2
(b) Area of enclosed circle =πr2
=7/22×7×7
=154 cm2
Area of enclosed four circles =4×156=616 cm2
∴ Area of shaded part =784−616=168 cm2
3. Area of remaining portion = Area of trap - Area of quadrant
= 1/2 x 3.5 (5.5 + 3.5) - 1/4 x 22/7 x3.5x3.5
= 15.75 - 19.25/2 = 15.75 - 9.625
= 6.125 cm2