Can someone please solve this??
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no instead of m² on the rhs it should be 2m because the square power(2) will come out and it will get multiplied by m to form 2m.
inkeminkem168:
Ok... please just answer this..
you can't solve this, you have to prove this that LHS=RHS and I just told you the correct way to solve it.
Ohh..yeah right. Thanks.
But then what is that m#0 (m not equals 0)?
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(4/25)^m=(x/5)^2m
(4/25)^m=(x^2/25)^m
(4/25)=(x^2/25)
4=x^2
x=2/-2
(4/25)^m=(x^2/25)^m
(4/25)=(x^2/25)
4=x^2
x=2/-2
But x isn't there..
sorry i thought 2 was a question mark
now i can't dellete my ans
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