Math, asked by Anonymous, 8 months ago

can someone please solve this question and give the explanation . I request no spammers

Attachments:

Answers

Answered by Anonymous

Answer:

$\sin( \alpha ) + \csc( \alpha ) = 2 \\ \\ \sin( \alpha ) + \frac{1}{ \sin( \alpha ) } = 2 \\ \\ \frac{ { \sin}^{2} \alpha + 1 }{ \sin( \alpha ) } = 2 \\ \\ { \sin }^{2} \alpha + 1 - 2 \sin( \alpha ) = 0 \\ \\ { (\sin( \alpha ) + 1) }^{2} = 0 \\ \\ \sin( \alpha ) = 1 \\ \\ \csc( \alpha ) = \frac{1}{ \sin( \alpha ) } = \frac{1}{1} \\ \\{ \sin}^{n} \alpha + { \csc}^{n} \alpha = \\ \\ 1 + 1= 2\\ \\$

Answered by Anonymous

$<html><body> <marquee style="z-index:2;position:absolute;left:18px;top:97px;font-family:Cursive;font-size:14pt;color:#ffcc00;height:200px;" scrollamount="3" direction="down">☠️MethaZeher ☠️</marquee> <marquee style="z-index:2;position:absolute;left:1px;top:89px;font-family:Cursive;font-size:14pt;color:#ffcc00;height:100px;" scrollamount="7" direction="down">☠️MethaZeher ☠️</marquee> <marquee style="z-index:2;position:absolute;left:111px;top:7px;font-family:Cursive;font-size:14pt;color:#ffcc00;height:302px;" scrollamount="4" direction="down">♥️follow me♥️</marquee> <marquee style="z-index:2;position:absolute;left:225px;top:83px;font-family:Cursive;font-size:14pt;color:#ffcc00;height:371px;" scrollamount="3" direction="down">☠️Methazeher☠️</marquee> <marquee style="z-index:2;position:absolute;left:105px;top:53px;font-family:Cursive;font-size:14pt;color:#ffcc00;height:317px;" scrollamount="2" direction="down">♥️follow me♥️</marquee></body> </html>$