Math, asked by Anonymous, 10 months ago

can someone please solve this question and give the explanation . I request no spammers

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Answered by Anonymous

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$\sin( \alpha ) + \csc( \alpha ) = 2 \\ \\ \sin( \alpha ) + \frac{1}{ \sin( \alpha ) } = 2 \\ \\ \frac{ { \sin}^{2} \alpha + 1 }{ \sin( \alpha ) } = 2 \\ \\ { \sin }^{2} \alpha + 1 - 2 \sin( \alpha ) = 0 \\ \\ { (\sin( \alpha ) + 1) }^{2} = 0 \\ \\ \sin( \alpha ) = 1 \\ \\ \csc( \alpha ) = \frac{1}{ \sin( \alpha ) } = \frac{1}{1} \\ \\{ \sin}^{n} \alpha + { \csc}^{n} \alpha = \\ \\ 1 + 1= 2\\ \\$

Answered by Anonymous

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