Question

can someone pls complete this ​

Answer 1

ANSWER = (-11)

LHS

[{(2/5)^2}^4]^x+2 = (2/5 ) ^ (8x +16)

RHS

[{(2/5)^(-2))^(x-1)}^(-3)] = (2/5) ^ (6x -6)

Since LHS = RHS ,

(2/5) ^ (8x+16) = ( 2/5)^(6x-6)

the bases are equal ,

===> 8x + 16 = 6x -6

===> 8x - 6x = -22

===> 2x = -22

===> x = -11

Answer 2

Hope it's helpful to you :) :)