Question

Can someone pls help. ​

Answer 1

Step-by-step explanation:

clearly 216 = 6³ and 27 = 3³

so

$6x^{3} - { \frac{1}{3} }^{3}$

so by applying formula of a³ - b³ = (a+b) (a-b)

$6x^{3} - { \frac{1}{3} }^{3} = 6x + \frac{1}{3} \times 6x - \frac{1}{3}$

18x + \frac{1}{3} \times 18x - \frac{1}{3} [/tex]

Answer 2

HEYA MATE HERE'S YOUR ANSWER ⬇️

216 x³ - 1/27

=> (6x)³ - (1/3)³

$a^3 - b^3 = (a – b) (a^{2} + ab + b^{2})$

=> {6x-1/3}(36x²+2x+1/9).

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