Question

can someone pls help me with the 13th question...

Answer 1

Let the total number of students in the school be x

Given, total number of boys 1023

% of girls = 38%

% of boys = 100 - 38% = 62%


According to the question,

x × $\dfrac{38}{100}$ = 1023

x = 1023 × $\dfrac{100}{38}$

x = $\dfrac{102300}{38}$

x = 1650



Total strength of the school => x

=> $\tt \bf {1650}$


Total number of boys => 1023


Total nunber of girls => 1650 - 1023

=> 627