Can someone pls solve q.no. 2 for me....pls help me frnds...I need your help...plsssss
Attachments:
Answers
Answered by
1
Answer is 3)6.75 as the rate is second order for A and first order for B
Therefore rate becomes (1.5)^2*3=6.75.
Hope my answer helps you
Please mark me as brainliest
Regards,
Adira.
Therefore rate becomes (1.5)^2*3=6.75.
Hope my answer helps you
Please mark me as brainliest
Regards,
Adira.
KunalVerma911:
oops sorry
But thank u so much...Adira nd Kunal....u both have helped me a lot....i was stuck in this question...and I came to know that I was doing some kind of silly mistake here....
No need to say sorry frnd.......U noth owe me a lot....Thnk u so much my dear new frnds.
love u both...Bye and take care
Aww thank you so much for those kind words. People so well-mannered like you are hard to find these days.
love you too,bye!
Hello Adira.I apologise for my arrogance.
No not at all,it’s fine.
Thnk u Adira.....well it applies to u both as well...U both are really nice.
Thank you so much^_^
Answered by
1
The rate equation is
R=k[A]^½[B]²
If concentration of A is increased 4 times then its final concentration is 4A and similarly final concentration of B is 2B.
so putting these values in rate equation we get
R'=k[4A]½[2B]²
or,R'=k x 2[A]^½ x 4[B]²
or,R'=8k[A]^½[B]²
or,R'=8R
so answer is C 8 times
Hope it helps.
R=k[A]^½[B]²
If concentration of A is increased 4 times then its final concentration is 4A and similarly final concentration of B is 2B.
so putting these values in rate equation we get
R'=k[4A]½[2B]²
or,R'=k x 2[A]^½ x 4[B]²
or,R'=8k[A]^½[B]²
or,R'=8R
so answer is C 8 times
Hope it helps.
Thnk u so much frnd......your helping attitude is truely incredible.Thnk u so so much for lending me your precious time.
And thnk u once again my frnd...for answering q.no.2 as well....I was goin gto ask that too...it eased my work tho...thnk u so much.
But frnd...I have a doubt here..it says that initial conc.is increased by a 'FACTOR' of 4....so why it can't be.....-(A+4)then?
Sry frnd,but that's not aNnegative sign in front of (A+4)...it's just simply(A+4)
If anything is said to be increased by a factor of something then it always implies multiplication.
Okh...i got it...so it means that if the question said just increased....instead of increased by a factor....then it would 've been addition...i suppose?
Similar questions